What is the value of √(-25) + 3√(-4) + 2√(-9)?

To solve √(-25) + 3√(-4) + 2√(-9), handle the square roots of negative numbers using imaginary units. Step 1: Compute each term: √(-25) = √(25 × -1) = 5i; 3√(-4) = 3√(4 × -1) = 3 × 2i = 6i; 2√(-9) = 2√(9 × -1) = 2 × 3i = 6i. Step 2: Sum the results: 5i + 6i + 6i = 17i. Verify: Each term is purely imaginary, and no real parts exist. Options A (15i), C (19i), and D (21i) do not match the sum. Thus, the correct answer is B.