Two concentric circles are of radii 10 cm and 6 cm. Find the length of the chord of the larger circle which touches the smaller circle:

The chord of the larger circle (radius 10 cm) touches the smaller circle (radius 6 cm), forming a right triangle with the center. The distance from the center to the chord is 6 cm (radius of smaller circle). Chord length = 2 × √(10² - 6²) = 2 × √(100 - 36) = 2 × 8 = 16 cm. Studying this highlights geometry, providing lessons for design applications.